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(5w^2)-(10w)=0
a = 5; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·5·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*5}=\frac{0}{10} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*5}=\frac{20}{10} =2 $
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